From: Simon Baird <simon.baird@...>
Date: 2006-07-28T13:19:00+09:00
Subject: Re: Equivalent of perl's \Q in regexps?

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On 7/28/06, Logan Capaldo <logancapaldo@gmail.com> wrote:
>
>
> On Jul 27, 2006, at 9:10 PM, Simon Baird wrote:
>
> > marker = '***'
> >
> > code = <<-EOT
> > var x = 1
> > //*** hello
> > function foo() {}
> > EOT
> >
> > p code.to_a.grep(/\*\*\*/)          # -> ["//*** hello\n"]   that's
> > what I
> > want but using marker
> >
> > #p code.to_a.grep(/#{marker}/)      # -> invalid regexp error
> >
> > p code.to_a.grep(/#{%q(marker)}/)   # -> [], doesn't work
> >
> >
> >
> > In perl you can do /\Q$marker/ and it escapes $marker for the regexp.
> >
> >
>
> Just guessing but I believe you want
> /#{Regexp.escape(marker)}/
>
> or Regexp.new(Regexp.escape(marker))



Cool. It works. Thanks

Not quite as pretty as I'd like. Maybe a %R(...) would be a nice sweetener.
Simon.
-- 
Simon Baird <simon.baird@gmail.com>

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