From: Daniel Baird <danielbaird@...>
Date: 2006-07-28T10:27:37+09:00
Subject: Re: Equivalent of perl's \Q in regexps?

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On 7/28/06, Simon Baird <simon.baird@gmail.com> wrote:
>
> marker = '***'
>
> code = <<-EOT
> var x = 1
> //*** hello
> function foo() {}
> EOT
>
> p code.to_a.grep(/\*\*\*/)          # -> ["//*** hello\n"]   that's what I
> want but using marker
>
> #p code.to_a.grep(/#{marker}/)      # -> invalid regexp error
>
> p code.to_a.grep(/#{%q(marker)}/)   # -> [], doesn't work
>
>
>
> In perl you can do /\Q$marker/ and it escapes $marker for the regexp.
>
>
> Simon.
>
> --
> Simon Baird <simon.baird@gmail.com>
>
>

Maybe you want %r:

regex = %r{^\s*[a-z]}

-- 
Daniel Baird
http://tiddlyspot.com (free, effortless TiddlyWiki hosting)
http://danielbaird.com (TiddlyW;nks! :: Whiteboard Koala :: Blog :: Things
That Suck)

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