From: Austin Ziegler <halostatue@...>
Date: 2006-07-05T04:23:51+09:00
Subject: Re: About 1.9 #__method__ feature.

On 7/4/06, Yukihiro Matsumoto <matz@ruby-lang.org> wrote:
> Ah, maybe I didn't express myself clear.
>   obj.send(:foo, args)
> does work like
>   obj.foo(args)
> and
>   obj.funcall(:foo, args)
> works like
>   foo(args)

So:

  class Foo
    def foo(*args)
    end
    private :foo

    def bar(*args)
    end
  end

  obj = Foo.new

  obj.foo(5)            # Throws an error, just as now.
  obj.send(:foo, 5)     # ???
  obj.funcall(:foo, 5)  # ???

Will #funcall be the way that I can circumvent private?

-austin
-- 
Austin Ziegler * halostatue@gmail.com * http://www.halostatue.ca/
               * austin@halostatue.ca * http://www.halostatue.ca/feed/
               * austin@zieglers.ca