From: Mark Van Holstyn <mvette13@...>
Date: 2006-06-26T04:04:46+09:00
Subject: Re: expecting kEND

------=_Part_11976_31644374.1151262283694
Content-Type: text/plain; charset=ISO-8859-1; format=flowed
Content-Transfer-Encoding: 7bit
Content-Disposition: inline

You need matching ends for def, if and do...

def roman num

 if num <= 4
   i = 1
   rn = (num/i)
   rn.times do
     print "I"
   end

 else num >= 5 && num <= 9
   v = 5
   rn = (num/v)
   rnm = (num%v)
   rn.times do
     print "V"
   end
   rnm.times do
     print "I"
   end
 end

end



On 6/25/06, Dark Ambient <sambient@gmail.com> wrote:
>
> I know this is a literal translation to keyword end, but unsure
> sometimes (right now that is frequent) of where end goes.  I know
> there is one to end the method definition.
> However adding one after the if and one after the else , or just one
> for both conditions doesn't seem to help.
>
> def roman num
>
>   if num <= 4
>     i = 1
>     rn = (num/i)
>     rn.times do
>     print "I"
>
>   else num >= 5 && num <= 9
>     v = 5
>     rn = (num/v)
>     rnm = (num%v)
>     rn.times do
>       print "V"
>     rnm.times do
>       print "I"
>
> end
>
>


-- 
Mark Van Holstyn
mvette13@gmail.com
http://lotswholetime.com

------=_Part_11976_31644374.1151262283694--