From: ts <decoux@...>
Date: 2001-08-14T14:17:45+09:00
Subject: [ruby-talk:19675] Re: () overloading

>>>>> "E" == Ed Sinjiashvili <edsin@swes.saren.ru> writes:

E> ts <decoux@moulon.inra.fr> writes:
>> >>>>> "E" == Ed Sinjiashvili <edsin@swes.saren.ru> writes:
>> 
E> class Proc
E> def () (*args)
E> call(*args)
E> end
E> end
>> 
>> Proc#call use () which call Proc#(), which call Proc#call which use ()
>> which call Proc#(), etc ... :-)))
E> Proc#call is an instance of class Method - so it can not call Proc#() -
E> unless you somehow override Method#() to use it. 

 I'll write it another way (just replace () with tt)

   class Proc
      def tt *args
         call tt *args
      end
   end


Guy Decoux