From: Ed Sinjiashvili <edsin@...>
Date: 2001-08-14T14:12:11+09:00
Subject: [ruby-talk:19674] Re: () overloading

ts <decoux@moulon.inra.fr> writes:

> >>>>> "E" == Ed Sinjiashvili <edsin@swes.saren.ru> writes:
> 
> E> class Proc
> E>   def () (*args)
> E>     call(*args)
> E>   end
> E> end
> 
>  Proc#call use () which call Proc#(), which call Proc#call which use ()
> which call Proc#(), etc ... :-)))
Proc#call is an instance of class Method - so it can not call Proc#() -
unless you somehow override Method#() to use it.