From: Harris Reynolds <hreynolds2@...>
Date: 2006-06-09T09:47:00+09:00
Subject: Re: Converting 8 bytes to a Float

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I am still not getting the results I am looking for hacking around with the couple suggestions I received.  Here is an example:
 
bytes = Array.new(8)
bytes[0] = 64
bytes[1] = 53
bytes[2] = 0
bytes[3] = 0
bytes[4] = 0
bytes[5] = 0
bytes[6] = 0
bytes[7] = 0
 
Calling:
 
binary_string = bytes.pack('D') 
 
returns a binary string, but not the float which should be 21.0; if I turn around and call
 
binary_string.unpack('d'), I end up with the original bytes.
 
It is turning out that getting from bytes to a Float object is a bit painful.  Is there something easy I am missing?
 
thanks,
 
~harris


----- Original Message ----
From: Timothy Hunter <TimHunter@nc.rr.com>
To: ruby-talk ML <ruby-talk@ruby-lang.org>
Sent: Thursday, June 8, 2006 8:26:52 PM
Subject: Re: Converting 8 bytes to a Float


Harris Reynolds wrote:
> What is the quickest way to convert 8 bytes to a Float object?
>  
> thanks for any help,
>  
> ~harris
>   
ri Array#pack

flt = arr.pack('D')
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