From: ts Date: 2001-08-13T22:36:24+09:00 Subject: [ruby-talk:19637] Re: () overloading >>>>> "E" == Ed Sinjiashvili writes: E> class Proc E> def () (*args) E> call(*args) E> end E> end Proc#call use () which call Proc#(), which call Proc#call which use () which call Proc#(), etc ... :-))) Guy Decoux