From: cdc@...2go.com (Cliff Cyphers)
Date: 2006-06-07T10:40:56+09:00
Subject: Re: regex for splitting filenames

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On Wed, Jun 07, 2006 at 10:30:23AM +0900, darren kirby wrote:
> Hello all,=20
>=20
> I want to split a filename into it's root and extension, ie:
> someFileName.txt =3D 'someFileName' and 'txt'
>=20
> This is simple enough with string.split(), but what if the file has more =
than=20
> one period in it? I have worked around this by doing:
>=20
> filename =3D "some.file.name.txt"
> temp =3D filename.split(".")
> type =3D temp.pop
> fileroot =3D temp.join(".")
>=20
> I was wondering though if instead of the temp variable I could just do:
>=20
> fileroot, type =3D filename.split(/regex here?/)
>=20
> I cannot find a way to write a regex that only matches the last period in=
 the=20
> filename. Is there an elegant way to do this?
>=20
> Thanks,
> -d
> --=20
> darren kirby :: Part of the problem since 1976 :: http://badcomputer.org
> "...the number of UNIX installations has grown to 10, with more expected.=
=2E."
> - Dennis Ritchie and Ken Thompson, June 1972

base =3D ("#{filename}"[0..("#{filename}".rindex('.')-1)])

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