From: Han Holl <han.holl@...>
Date: 2006-05-21T18:46:44+09:00
Subject: How to reverse String.unpack('H*')

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Hello rubyists,

I have binary numbers that through an ODBC interface are decoded with
String.unpack('H*').

Let's give an example: the number 23.

b=3D'xxxx'
b[0]=3D23; b[1] =3D b[2] =3D b[3] =3D 0

b.unpack('I')  =3D>  [23]
b.unpack('H*') =3D> ["17000000"]

The problem: how do I convert "17000000" to 23 ?

The following works, but seems awfully complex:
fl =3D "17000000"
fl.unpack('a2a2a2a2').collect {|x| "0x#{x}".hex}.pack('I').unpack('I')[0]

Any suggestions ?

Han Holl

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