From: Michael Gorsuch <michael.gorsuch@...>
Date: 2006-05-15T08:36:04+09:00
Subject: Re: begining programmer questions

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'gets' will read a string from input and build a new string object.

When you did 'info =3D gets.chomp', you wiped out your array and made it a
simple String object.

'exit' is being stored because your program logic is placing the string int=
o
the Array, and then checking to see if the last retrieved value is 'exit'.

You may be better off using a temporary variable first, checking it, and
then storing it.

On 5/14/06, corey konrad <0011@hush.com> wrote:
>
> oh ok basicly the issue is that i just didnt  understand what the gets
> method was doing, it was creating another string? Wow i thought it just
> GOT another string i didnt know it created one. Thats really confusing.
> Puts and Gets have been really confusing methods for me so far.
>
> also why does puts #{info} always print exit even if a user doesnt type
> that in, that doesnt make sense to me at all.
>
>
>
> Michael Gorsuch wrote:
> > Ah!
> >
> > Take a look here:
> >
> > "info =3D gets.chomp"
> > You've just changed 'info' into a String.
> >
> > Instead, do this:
> >
> > "info << gets.chomp"
> >
> > This means 'get some stuff, chomp it, and add it to the info Array'
>
>
> --
> Posted via http://www.ruby-forum.com/.
>
>

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