From: Michael Gorsuch <michael.gorsuch@...>
Date: 2006-05-15T07:37:11+09:00
Subject: Re: begining programmer questions

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while info[] !=3D "exit"

this line is giving the error.

The '[]' piece expects an integer to placed in there to reference the
array.  For example, info[0] or info[53].

I suggest something similar to this:

def input
  puts "Enter some info"
  info =3D []
  while (data =3D gets.chomp) !=3D 'exit'
    info << data
  end
  info.sort!
  puts info
end



On 5/14/06, corey konrad <0011@hush.com> wrote:
>
> well i tried what you said but i still get an error now, it says that i
> have the wrong number of arguments. I know it isnt that important of
> program but i just dont understand the error messages.
>
> def input
>   puts "Enter some info"
>   info =3D []
>   info << gets.chomp
> while info[] !=3D "exit"
> info << gets.chomp
> end
> info.sort
> puts "#{info}"
> end
>
>
>
> corey konrad wrote:
> > ok thanks for the help
> >
> >
> >
> > Michael Gorsuch wrote:
> >> I suppose it could, but I think the easiest way to build an Array in
> >> ruby is
> >> as follows:
> >>
> >> info =3D []
> >>
> >> You can build a Hash via:
> >>
> >> info =3D {}
>
>
> --
> Posted via http://www.ruby-forum.com/.
>
>

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