From: Sergey Volkov <gm.vlkv@...>
Date: 2006-05-14T03:27:22+09:00
Subject: Re: list folder content from win directory -> xml output

just to continue after previous start :) :
#
open( "all_files.xml", "w" ){ |out|
    out.puts "<all_files>"
    Dir["**/*"].each{ |f| out.puts "  <file>#{f}</file>" }
    out.puts "</all_files>"
}
#
this code outputs list of all files in output file in xml format: 
'all_files.xml';

resources: you can start with
http://www.rubycentral.com/book/
http://www.ruby-lang.org/en/

enjoy
Sergey

----- Original Message ----- 
From: "jonas tr" <jonas.tracht@gmail.com>
Newsgroups: comp.lang.ruby
To: "ruby-talk ML" <ruby-talk@ruby-lang.org>
Sent: Saturday, May 13, 2006 1:52 PM
Subject: Re: list folder content from win directory -> xml output


> Thanx Sergey,
>
> so how do I transfer the lot into an xml file?
> anybody, have a hint? maybe somebody can point me to valuable resources.
> any help is higly appreciated!
> thx,
> jonas
>
> -- 
> Posted via http://www.ruby-forum.com/.
>