From: Dave Thomas <Dave@...>
Date: 2001-08-07T04:33:11+09:00
Subject: [ruby-talk:19247] Re: re

markus liedl <markus.lado@gmx.de> writes:

> i'm just not understanding it...
> 
> "z u i u" =~ /(z|u|\s)+/
> p $1

You've asked it to match the longest possible string of 'z', 'u', or
whitespace characters. So, it went and matched 'z u '. The last of the
characters matched is ' ', so that's what is returned in $1.

You can see the complete match in $& (which is indeed "z u ").

Regards


Dave