From: "Berger, Daniel" <Daniel.Berger@...>
Date: 2006-04-18T01:11:25+09:00
Subject: Re: Regular expression to parse out "host" part of URL strin

> -----Original Message-----
> From: list-bounce@example.com 
> [mailto:list-bounce@example.com] On Behalf Of Wes Gamble
> Sent: Monday, April 17, 2006 10:05 AM
> To: ruby-talk ML
> Subject: Re: Regular expression to parse out "host" part of URL strin
> 
> 
> Daniel,
> 
> I have that :).
> 
> I'm trying to handle the case when I get a "URL" without the http://
> 
> Wes

Instead of beating yourself up trying to come up with a regex, just
stick the 'http://' in front of it yourself.

unless path.index('http://', 0)
   path = 'http://' + path
   host = URI.parse(path).host
end

It's not necessarily the most robust solution, but you get the general
idea.

Regards,

Dan