From: Wes Gamble <weyus@...>
Date: 2006-04-18T01:04:57+09:00
Subject: Re: Regular expression to parse out "host" part of URL strin

Daniel,

I have that :).

I'm trying to handle the case when I get a "URL" without the http://

Wes

Berger, Daniel wrote:
>> I am trying to write a regex to parse out the "host" part of 
>> a potential 
>> URL.
> 
> require 'uri'
> 
> URI.parse('http://www.cnn.com').host # www.cnn.com
> URI.parse('http://www.cnn.com/').host # www.cnn.com
> URI.parse('http://www.cnn.com/some/other/stuff').host # www.cnn.com
> 
> You'll have to prepend the 'http://' yourself.
> 
> Regards,
> 
> Dan


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