From: Wes Gamble <weyus@...>
Date: 2006-04-18T00:39:13+09:00
Subject: Regular expression to parse out "host" part of URL string

All,

I am trying to write a regex to parse out the "host" part of a potential 
URL.

So if presented with

www.cnn.com

I want to get

www.cnn.com

If presented with

www.cnn.com/

I want to get

www.cnn.com

If presented with

www.cnn.com/some/other/stuff

I want to get

www.cnn.com

This regex:  /(.*)?\/*/  matches everything
This regex:  /(.*)?\// matches everything including the "/"

How can I just get the part of the string before the slash?

Thanks,
Wes

-- 
Posted via http://www.ruby-forum.com/.