From: petermichaux@...
Date: 2006-04-02T06:28:46+09:00
Subject: Re: Regexp grouping question


Chris Alfeld wrote:
> compressed = "foo = bar; red  = herring;"
> compressed = compressed.gsub(/\s*([=;])\s*/,'\1')
>
> I believe #$1 is evalued *before* gsub is executed and hence fails.
> gsub sets the variable and uses \1, \2, \3 in the replacement string
> to correspond.

Thank you!

Peter