From: Meino Christian Cramer <Meino.Cramer@...>
Date: 2006-03-31T13:16:44+09:00
Subject: Re:

From: Timothy Bennett <timothy.s.bennett@gmail.com>
Subject: Re:
Date: Fri, 31 Mar 2006 06:22:37 +0900

Hi Tim,

 this gives an error with my recent "stable-snapshot-ruby":

   >> a = ("A".."Z" + "a".."z").sort_by { rand }
   SyntaxError: compile error
   (irb):1: syntax error, unexpected tDOT2
   a = ("A".."Z" + "a".."z").sort_by { rand }
                        ^
           from (irb):1
   >> 

 Keep hacking!
 mcc


> a = ("A".."Z" + "a".."z").sort_by { rand }
> 
> Tim
> 
> On Mar 30, 2006, at 1:11 PM, Meino Christian Cramer wrote:
> 
> > From: James Edward Gray II <james@grayproductions.net>
> > Subject: Re:
> > Date: Fri, 31 Mar 2006 05:39:15 +0900
> >
> > Hi,
> >
> >  sorry, me again.
> >
> >  If I want not only "a".."z" but also "A".."Z" I thought (from the
> >  logical point of view...) that
> >
> >>> a=("A".."z").sort_by { rand }
> >
> >  would work, but it gaves me:
> >
> >>> a
> >  => ["P", "D", "Q", "N", "H", "A", "M", "X", "G", "C",
> >      "E", "L", "I", "S", "B", "J", "F", "Y", "T", "Z", "V", "K",  
> > "O", "U", "R", "W"]
> >
> >  which isn't exactly, what I have exspected....
> >
> >  Unfortunately
> >
> >  a=("A".."Z").sort_by { rand } + ("a".."z").sort_by { rand }
> >
> >  would first randomize A->Z and then a->z and dont mix both.
> >
> >  Or am I not thinking too straight forward again ;)  ?
> >
> >  Keep hacking!
> >  mcc
> >
> >
> >
> >> On Mar 30, 2006, at 2:33 PM, Meino Christian Cramer wrote:
> >>
> >>> Hi;
> >>>
> >>>  I am looking for an algorithm, which spread all 26 letters of the
> >>>  alphabet over an array of 26 places randomly. All letters should be
> >>>  statistically equally handled.
> >>
> >> Well, this is only as good as the random number generator, but it
> >> sure is easy:
> >>
> >>>> ("a".."z").sort_by { rand }
> >> => ["s", "m", "q", "j", "f", "r", "z", "e", "l", "k", "y", "v", "g",
> >> "d", "x", "p", "w", "a", "b", "c", "i", "t", "h", "o", "u", "n"]
> >>
> >> Hope that helps.
> >>
> >> James Edward Gray II
> >>
> >
> 
>