From: Timothy Bennett Date: 2006-03-31T06:22:37+09:00 Subject: Re: a = ("A".."Z" + "a".."z").sort_by { rand } Tim On Mar 30, 2006, at 1:11 PM, Meino Christian Cramer wrote: > From: James Edward Gray II > Subject: Re: > Date: Fri, 31 Mar 2006 05:39:15 +0900 > > Hi, > > sorry, me again. > > If I want not only "a".."z" but also "A".."Z" I thought (from the > logical point of view...) that > >>> a=("A".."z").sort_by { rand } > > would work, but it gaves me: > >>> a > => ["P", "D", "Q", "N", "H", "A", "M", "X", "G", "C", > "E", "L", "I", "S", "B", "J", "F", "Y", "T", "Z", "V", "K", > "O", "U", "R", "W"] > > which isn't exactly, what I have exspected.... > > Unfortunately > > a=("A".."Z").sort_by { rand } + ("a".."z").sort_by { rand } > > would first randomize A->Z and then a->z and dont mix both. > > Or am I not thinking too straight forward again ;) ? > > Keep hacking! > mcc > > > >> On Mar 30, 2006, at 2:33 PM, Meino Christian Cramer wrote: >> >>> Hi; >>> >>> I am looking for an algorithm, which spread all 26 letters of the >>> alphabet over an array of 26 places randomly. All letters should be >>> statistically equally handled. >> >> Well, this is only as good as the random number generator, but it >> sure is easy: >> >>>> ("a".."z").sort_by { rand } >> => ["s", "m", "q", "j", "f", "r", "z", "e", "l", "k", "y", "v", "g", >> "d", "x", "p", "w", "a", "b", "c", "i", "t", "h", "o", "u", "n"] >> >> Hope that helps. >> >> James Edward Gray II >> >