From: Ruby Quiz Date: 2006-03-24T22:56:18+09:00 Subject: [QUIZ] B & E (#72) The three rules of Ruby Quiz: 1. Please do not post any solutions or spoiler discussion for this quiz until 48 hours have passed from the time on this message. 2. Support Ruby Quiz by submitting ideas as often as you can: http://www.rubyquiz.com/ 3. Enjoy! Suggestion: A [QUIZ] in the subject of emails about the problem helps everyone on Ruby Talk follow the discussion. -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-= by Stephen Waits Like many homeowners, I have a residential monitored alarm system installed in my house. It consists of a few keypads and several remote sensors. My alarm has three modes of operation: 1. Off - completely disarmed 2. Away - everything (perimeter and interior) armed 3. Stay - perimeter armed The keypad consists of 12 buttons, which includes the digits '0' through '9', plus '*' and '#'. The '*' and '#' are only used for special programming. The digits '1', '2', and '3' are also labeled "Off", "Away", and "Stay". This corresponds to the three system modes mentioned above. The security code is 4 digits long. To set or change the system's mode, you simply enter your 4 digit security code, followed by the digit ('1', '2', or '3') which corresponds to the mode you want to set. For example, if the security code was 1234: 12341 - sets system to "Off" 12342 - sets system to "Away" 12343 - sets system to "Stay" What if you make a mistake when you're entering your code? Yes, this is where an interesting observation comes into play. To answer the question... if you make a mistake you just start over. In other words, the keypad seems to only care that the last 5 keypresses match a valid code+command sequence. For example, if you entered the first two digits of your code incorrectly, you could just simply start over with the correct code, without any kind of reset: 8912341 ++ => first 2 keypresses erroneous, oops! +++++ => last 5 keypresses == valid code+command sequence The thought occurs to me, and I'm sure to the reader, that perhaps this can be exploited. For example, if you entered the sequence 1234123, you are actually testing 3 different codes: 1234123 => what you entered 12341 => 1234 + 1/off .23412 => 2341 + 2/away ..34123 => 3412 + 3/stay Problems: 1. What is the shortest sequence of digits you can come up with that tests every code in this alarm system? The worst case is 5*10**4, or 50000 keypresses. 2. What if the security code was 5 digits instead of 4? Worst case here is 6*10**5, or 600000 keypresses. 3. What if the "stop digits" changed from [1, 2, 3], to just [1]? For instance, maybe the system is armed (mode 2 or 3) and only actually beeps when switching to mode 1. (See Assumptions below) 4. Can you also minimize the number of duplicate code tests? Assumptions: * We assume the keypad will actually let you go on entering digits for this long. I haven't tested it, but it seems silly that it might actually allow this. However, as a long time comp.risks reader, almost nothing surprises me. * We assume that the keypad will always signify a valid code+command sequence, regardless of mode. In reality, if you set to Away when it's already in Away, it might not emit it's "success" signal. #!/usr/bin/env ruby -w # # Stephen Waits # class AlarmKeypad # init a keypad, with length of security code, and the code's # stop digits def initialize(code_length = 4, stop_digits = [1,2,3]) # remember the length of the security code @code_length = code_length # and which digits cause a code to be checked @stop_digits = stop_digits # and reset our data structures to 0 clear end # reset keypad to initial state def clear # an array of each code and how many times it's been entered @codes = Array.new(10**@code_length,0) # last N+1 keypad button presses @key_history = [] # total number of keypad button presses @key_presses = 0 end # press a single digit def press(digit) # add digit to key history @key_history.shift while @key_history.size > @code_length @key_history << digit @key_presses += 1 # see if we just tested a code if @stop_digits.include?(@key_history.last) and @key_history.length > @code_length @codes[@key_history[0,@code_length].join.to_i] += 1 end end # find out if every code had been tested def fully_tested? not @codes.include?(0) end # find out if an individual code has been tested # NOTE: an actual keypad obviously doesn't offer this functionality; # but, it's useful and convenient (and might save duplication) def tested?(code) @codes[code] > 0 end # output a summary def summarize tested = @codes.select { |c| c > 0 }.size tested_multiple = @codes.select { |c| c > 1 }.size puts "Search space exhausted." if fully_tested? puts "Tested #{tested} of #{@codes.size} codes " + "in #{@key_presses} keystrokes." puts "#{tested_multiple} codes were tested more than once." end end if $0 == __FILE__ # a random button presser, 3 digit codes a = AlarmKeypad.new(3) a.press( rand(10) ) until a.fully_tested? a.summarize # sequential code entry, 4 digit codes a = AlarmKeypad.new(4) ("0000".."9999").each do |c| next if a.tested?(c.to_i) c.split(//).each { |d| a.press(d.to_i) } a.press(rand(3)+1) end a.summarize # sequential code entry, 5 digit codes, only [1] as a stop digit a = AlarmKeypad.new(5,[1]) ("00000".."99999").each do |c| next if a.tested?(c.to_i) c.split(//).each { |d| a.press(d.to_i) } a.press(1) end a.summarize end