From: pere.noel@... (=?ISO-8859-1?Q?Une_b=E9vue?=)
Date: 2006-03-23T23:38:51+09:00
Subject: Re: perl regexp to ruby one conversion ?

James Edward Gray II <james@grayproductions.net> wrote:

> 
> The expression looks fine to me.  Did you try using it?

yes, without the correct result, here is my code :

field='&���!����tybvn�'
utf8rgx=Regexp.new('m/^(
   [\x09\x0A\x0D\x20-\x7E]            # ASCII
 | [\xC2-\xDF][\x80-\xBF]             # non-overlong 2-byte
 |  \xE0[\xA0-\xBF][\x80-\xBF]        # excluding overlongs
 | [\xE1-\xEC\xEE\xEF][\x80-\xBF]{2}  # straight 3-byte
 |  \xED[\x80-\x9F][\x80-\xBF]        # excluding surrogates
 |  \xF0[\x90-\xBF][\x80-\xBF]{2}     # planes 1-3
 | [\xF1-\xF3][\x80-\xBF]{3}          # planes 4-15
 |  \xF4[\x80-\x8F][\x80-\xBF]{2}     # plane 16
)*$/x')

the test :

flag=(field === utf8rgx)
p "flag = #{flag}"

the result being :
"flag = false"

i'm sure my encoding is utf-8...

may be i've a misunderstanding of "===" ?

because when trying :

truc = 'toto'
rgx=Regexp.new('^toto$')
flag=(truc === rgx)
p "flag = #{flag}"

i got :
# => "flag = false"      ///seems NOT OK to me

flag=(truc =~ rgx)
p "flag = #{flag}"
# => "flag = 0"          ///seems OK to me

-- 
une b�vue