From: ts <decoux@...>
Date: 2001-07-20T14:56:19+09:00
Subject: [ruby-talk:18176] Re: Enabling "super"

>>>>> "A" == Aleksei Guzev <aleksei.guzev@bigfoot.com> writes:

A> super should perform much much faster.

 Are you sure ?

 You are saying that rb_call() is much much faster than rb_funcall()

   VALUE
   #ifdef HAVE_STDARG_PROTOTYPES
   rb_funcall(VALUE recv, ID mid, int n, ...)
   #else
   rb_funcall(recv, mid, n, va_alist)
       VALUE recv;
       ID mid;
       int n;
       va_dcl
   #endif
   {
       va_list ar;
       VALUE *argv;
   
       if (n > 0) {
   	int i;
   
   	argv = ALLOCA_N(VALUE, n);
   
   	va_init_list(ar, n);
   	for (i=0;i<n;i++) {
   	    argv[i] = va_arg(ar, VALUE);
   	}
   	va_end(ar);
       }
       else {
   	argv = 0;
       }
   
       return rb_call(CLASS_OF(recv), recv, mid, n, argv, 1);
   }
   
   

 In this case, call rb_funcall2() :-)

   VALUE
   rb_funcall2(recv, mid, argc, argv)
       VALUE recv;
       ID mid;
       int argc;
       VALUE *argv;
   {
       return rb_call(CLASS_OF(recv), recv, mid, argc, argv, 1);
   }
   


Guy Decoux