From: Kevin Turner <kturner@...>
Date: 2006-02-26T02:04:14+09:00
Subject: Simple "pass-thru" SOAP4R web service

I'm trying to write a simple "pass-thru" web service using SOAP4R. This 
web service will take the message passed and write it as XML to a file.
I don't want the web service to have to understand the format of the 
incoming message,just write it to a file.  I also want the service to 
take the contents of an xml file and return it to the caller. I've 
played with the soap marshal methods, and got close but I think the 
answer is much easier than what I've been doing. I'm brand new to Ruby 
and would appreciate any advice.

Thanks,
-Kevin

INBOUND SOAP MESSAGE:

<?xml version='1.0'?>
<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:xsd="http://www.w3.org/2001/XMLSchema" 
xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
  <soap:Body>
    <postorder xmlns="http://testit.com/webservices">
      <request>
        <order_no>123</order_no>
        <order_date>20060216</order_date>
        <line_items>
          <item color="red">Sample item ONE</item>
          <item color="blue">Sample item TWO</item>
        </line_items>
      </request>
    </postorder>
  </soap:Body>
</soap:Envelope>

SIMPLE WEB SERVICE:

require 'soap/marshal'
require 'xmlsimple'

class Order

  def postorder(request)
    # How do I take request and write to file as xml?
    puts "inspect: #{request.inspect}"

    # Now I want the web service return message to
    # be the xml from a file.
    retxml = XmlSimple.xml_in('returnxml.xml')
    # The following is close but not right.
    # The caller gets a single string, not xml data.
    XmlSimple.xml_out(retxml)
  end


end

VALUE OF request.inspect

inspect: #<SOAP::Mapping::Object:0x2ecdb5c {}order_no="123" 
{}order_date="20060216" {}line_items=#<SOAP::Mapping::Object:0x2ecd61c 
{}item=["Sample item ONE", "Sample item TWO"]>>

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