From: Jeppe Jakobsen <jeppe88@...>
Date: 2006-02-12T10:39:59+09:00
Subject: Scanning a string for decimal numbers

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Seems I accidently got my text marked as a qoute in my last mail, so I'll
just send it a again:

Let me see if I got it right then. I'll like to use periods only for my
decimal numbers. I also need normal integers so 24. being accepted won't
matter. Will this fix the problems you presented?:
/[-+]?(\d+\.?\d*)(?=3D\s|$)/


I don't know if it takes care of the last problem, because I didn't
understand it.


2006/2/12, Jeppe Jakobsen <jeppe88@gmail.com>:
>
> 2006/2/12, Alexis Reigel <mail@koffeinfrei.org>:
> >
> > >
> > > This should handle periods or commas as the separator.
> > >
> > > a =3D "24,4 + 55,2 + 55 - 44,0"
> > >    =3D> "24,4 + 55,2 + 55 - 44,0"
> > > a.scan /(\d+,?.?\d*)(?=3D\s|$)/
> > >    =3D> [["24,4"], ["55,2"], ["55"], ["44,0"]]
> > >
> >
> > Some problems here:
> > - signs are disregarded ("-24,4" becomes "24,4")
> > - Invalid numbers are accepted: eg. "24,.4" "24,." "24." "24,"
> > - "." should be escaped. As you used it here, it means "any character"
> > (except newline), so many invalid numbers are accepted (e.g. "24w"...)
> > - If something different from whitespace follows the number, it is not
> > or false accepted, e.g. "24.4." becomes "4." instead of "24.4"
> > - ...
> >
> >
> > Alexis.
>
>

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