From: diz rael <dizraelus@...>
Date: 2006-01-25T18:40:44+09:00
Subject: Re: subsequence regular expression

Thanks a lot for the suggestions. This is close to
what I'm looking for, but I don't quite get the effect
of "?:"

The docs say that it simply makes the regexp into a
group without generating backreferences. Doesn't this
mean that *not* using ?: will only have the
side-effect of setting $1, $2, etc.

However,:
   p s.scan(/(ba){2,}|([^b][^a])+/)
=> [[nil, "60"], ["ba", nil], [nil, "a9"]]

Another thing is that in the sample string in my
original post, the first "ba" happens to occur on an
odd location (string indexed from 0). If I shift it
forward by a character it doesn't work as well:

s =
"5b3000ba00260bababababababababababababababababa000bd1007bd10b810ba92"
p s.scan(/(?:ba){2,}|(?:[^b][^a])+/)
=> ["5b3000", "a00260",
"bababababababababababababababababa",
"000bd1007bd10b810ba9"]

ideally, it should be:
=> "5b3000ba00260"
"bababababababababababababababababa"
"000bd1007bd10b810ba92"

Thanks in advance..


--- Simon Strandgaard <neoneye@gmail.com> wrote:
> s =
>
"5b300ba00260bababababababababababababababababa000bd1007bd10b810ba92"
> p s.scan(/(?:ba){2,}|(?:[^b][^a])+/)
> #["5b300ba00260",
> "bababababababababababababababababa",
> "000bd1007bd10b810ba9"]
> 
> 
> --
> Simon Strandgaard


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