From: Sky Yin Date: 2006-01-25T07:21:24+09:00 Subject: Re: split up days oops, the last line should be: days = (Date.new(date_start)..Date.new(date_stop)).to_a On 1/24/06, Sky Yin wrote: > It's easy to transfer the string "year, month, day" to the parameter > format that meets the requirement of Date.new(year, month, day) : > > date_start = @start.split(',').map {|x|, x.to_i} > date_stop = @stop.split(',').map {|x|, x.to_i} > days = (Date.new(@start)..Date.new(@stop)).to_a > > Still elegant? > > On 1/24/06, misiek wrote: > > Sky Yin wrote: > > > Range can help you. Example: > > > > > > > > >>>require 'date' > > >>>days = (Date.new(2006,1,20)..Date.new(2006,1,24)).to_a > > >>>days.each {|date| puts date} > > > > > > =>2006-01-20 > > > =>2006-01-21 > > > =>2006-01-22 > > > =>2006-01-23 > > > =>2006-01-24 > > > > > > :^) > > > > > > > this is super but why when I will put 2006,3,2 into variable > > like @start = "2006,1,3" and @stop = "2006,1,4" does not work ? > > days = (Date.new(@start)..Date.new(@stop)).to_a > > > > > > undefined method `-' for "2006,1,3":String > > > > > > > -- > Blog >>> http://spaces.msn.com/members/skyincookoo > -- Blog >>> http://spaces.msn.com/members/skyincookoo