From: Christer Nilsson <janchrister.nilsson@...>
Date: 2005-12-31T10:36:50+09:00
Subject: Re: Numeric Maze (#60)

Jim Freeze wrote:
> we either have:
> 
>   double
>   halve (evens only)
>   add_two
>   times_one
> 
> so we can get (1,1) #=> [1,1]
> 
> or, we use the original tranformations to get:
> 
>   (1,1) #=> [1,2,1]

My suggestion is:

consider the original transformations having cost one. The new 
operation, times_one, will have cost zero. Find the minimum cost 
transforming a to b.

Hmm, this is getting interesting...

Christer

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