From: Edward Faulkner <ef@...>
Date: 2005-12-23T09:04:22+09:00
Subject: Re: correct terminology for a function that yields

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On Fri, Dec 23, 2005 at 09:00:31AM +0900, Joe Van Dyk wrote:
> def foo
>   yield
> end
>=20
> foo do
>   puts "hey"
> end
>=20
>=20
> What's the correct description of what is going on there?  I've got a
> function foo.  No arguments, right?  Does it "take a block"?  I know
> it gives control to the block, but I'm not sure of the correct
> terminology to use.

It does indeed "take a block".  The block argument is implicit.  You
could make it explicit if you wanted to:

def foo(&blk)
    blk.call
end

In more general terms, any function that takes another function as an
argument (or returns one as a result) is known as a higher-order
function.

regards,
Ed

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