From: Bill Kelly <billk@...>
Date: 2005-12-15T11:05:02+09:00
Subject: Re: regular expressions question

Hi,

From: "ako..." <akonsu@gmail.com>
>
>i give up. there seems to be no way to get all the captures for a
> group. the corresponding $ variable just has the last one.

Could you help us to understand why #scan didn't meet your needs?

Called without a block, #scan returns an array of matches:

>> "abc--------abc--------abc".scan(/(a)(b)(c)/)
=> [["a", "b", "c"], ["a", "b", "c"], ["a", "b", "c"]]

Called with a block, #scan calls your block each time a match is
found:

>> "abc--------abc--------abc".scan(/(a)(b)(c)/) { puts "#$1, #$2, #$3" }
a, b, c
a, b, c
a, b, c


Hope this helps,

Bill