From: "Kroeger, Simon (ext)" <simon.kroeger.ext@...>
Date: 2005-12-14T00:36:44+09:00
Subject: Re: stable sort_by?

 
I guess you have to use sort instead of sort_by in such a case,
like:

test = [[1, 'b'], [1, 'c'], [1, 'a'], [0, 'a']]

#sort for first item, than for second in reverse order
p test.sort{|a, b|(a[0] <=> b[0]).nonzero? || (b[1] <=> a[1]) }

=>[[0, "a"], [1, "c"], [1, "b"], [1, "a"]]

cheers

Simon

> -----Original Message-----
> From: list-bounce@example.com 
> [mailto:list-bounce@example.com] On Behalf Of Mike Fletcher
> Sent: Tuesday, December 13, 2005 3:57 PM
> To: ruby-talk ML
> Subject: Re: stable sort_by?
> 
> Frederick Ros wrote:
> >  h.sort_by {|k,v| [v[:a],v[:b],v[:c],v[:d]]}.reverse
> 
> OK, this or something like it should be in the rdoc for 
> sort_by.  I was 
> doing something similar and wound up writing a similar sort with 
> multiple if tests like the OP because I didn't remember that Array 
> implements a sane <=>.
> 
> Also, would there be a similar cool way to do this in one 
> step where you 
> want a mix of ascending and descending sorts on different 
> parts?  Say I 
> had a hash (in YAML):
> 
> Bobby:
>   age: 11
>   lastname: Smith
> Suzy:
>   age: 13
>   lastname: Jones
> Ted:
>   age 12
>   lastname: Smith
> 
> And I wanted to sort
>   - alphabetically by lastname
>   - then age oldest to youngest
> 
> So in Perl I'd do something like:
> 
> my @sorted_keys = sort { $a->{lastname} cmp $b->{lastname}
>                                         || $b->{age} <=> $a->{age} } 
> keys %data;
> 
> In this case I could use
> 
> sorted_keys = data.sort_by { |k,v| [ v["lastname"], -1*v["age"] ] }
> 
> But what if I wanted reverse alphabetically by lastname 
> (Z-A)?  In perl 
> I'd swap $a and $b in the first comparison, but I can't think of a 
> spiffy way to do the same using sort_by.
> 
> -- 
> Posted via http://www.ruby-forum.com/.
> 
>