From: Daniel Sheppard <daniels@...>
Date: 2005-12-09T06:05:49+09:00
Subject: Re: Are my metaprogramming underpants showing?

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> Given that the code below is functionally equivalent, what's =20
> beneficial about using a lambda expression?  It strikes me as a =20
> requirement imposed by using the Functor class more than anything.

The class way is definitely the way to go, as it gives you easier flexibi=
lity. I was just in a lamdba mood at the time I wrote it and couldn't be =
bothered making it into a class.

You might want to do this:

class Flickr
=20 instance_methods.each {|x| remove_method(x) unless /__.*__/ =3D=3D=3D=
=20x }
end

To prevent any conflict between flickr methods and ruby object methods.








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