From: Neil Stevens <neil@...>
Date: 2005-12-06T00:17:34+09:00
Subject: Re: increasing counter whithin loop?

Patrick Gundlach wrote:
> Hi,
> 
> a very basic question...
> 
> I'd like to output the sequence "a b d e", by testing if the current
> element is == "b" then skip the next element and continue the loop. The
> obvious solution doesn't look rubyish to me, how could I use the first
> or second attempt to get the desired solution?

array = [1, :skip, :hidden, 2, :skip, :hidden, 3, :skip]

# Zipped to ensure i is uniquely index()ed
# Also makes sure use array non-destructively
zip = array.zip
for i in zip
	if i[0] == :skip
		zip.delete_at(zip.index(i) + 1)
	else
		puts i[0]
	end
end

Output:

1
2
3

-- 
Neil Stevens - neil@hakubi.us

'A republic, if you can keep it.' -- Benjamin Franklin