From: "Kroeger, Simon (ext)" <simon.kroeger.ext@...>
Date: 2005-12-05T23:13:46+09:00
Subject: Re: increasing counter whithin loop?

perhaps:

a.inject(false) do |skip, elt| 
  puts elt if !skip
  elt=="b"
end 

(no, I don't think this is realy nice)

cheers

Simon

> -----Original Message-----
> From: Patrick Gundlach [mailto:clr9.10.randomuser@spamgourmet.com] 
> Sent: Monday, December 05, 2005 3:08 PM
> To: ruby-talk ML
> Subject: increasing counter whithin loop?
> 
> Hi,
> 
> a very basic question...
> 
> I'd like to output the sequence "a b d e", by testing if the current
> element is == "b" then skip the next element and continue the 
> loop. The
> obvious solution doesn't look rubyish to me, how could I use the first
> or second attempt to get the desired solution?
> 
> Patrick
> --------------------------------------------------
> a=%w( a b c d e )
> 
> # incorrect, outputs "a b c d e"
> 0.upto(a.size - 1) do |i|
>   puts a[i]
>   if a[i]=="b"
>     # skip next element
>     # but i won't get affected
>     i += 1
>   end
> end
> 
> # incorrect, outputs "a b c d e"
> for i in 0...a.size
>   puts a[i]
>   if a[i]=="b"
>     # skip next element
>     # but i won't get affected
>     i += 1
>   end
> end
> 
> # incorrect, outputs nothing... is there a next_next ?
> a.each do |elt|
>   puts elt
>   if elt=="b"
>     # skip next element
>     # ??
>   end
> end
> 
> # this one works, but is ugly
> i=0
> while i < a.size
>   puts a[i]
>   if a[i]=="b"
>     # skip next element
>     i += 1
>   end
>   i += 1
> end 
> 
>