From: David Boyd <david.a.boyd@...>
Date: 2005-11-18T20:01:02+09:00
Subject: Re: Ordinal Date String to Standard Date String for a Beginner

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Yeah, it's backwards in the PS -- just noticed it. (str.reverse won't
help!!!)

On 11/18/05, David Boyd <david.a.boyd@gmail.com> wrote:
>
> Botp, Todd,
>  Thanks. Since I had already parsed the ordinal date's year and day to ge=
t
> them in string sortable order, I just had to take your examples and do th=
is:
> require 'date' ... od =3D Date.ordinal (strYear.to_i, strOrdn.to_i ) and
> then od.to_s gives the sortable (and readable) yyyy-mm-dd string.
>  Wow, Ruby is powerful, but the documentation on Date (and perhaps other
> gem filled libraries) is hard for a beginner to grok. I found Date's ordi=
nal
> with a Google search, which gave me the built-in documentation, but no
> examples. So, if I need at least the APIs for a library such as Date I us=
e
> "ri"?
>  Thanks again,
>  Dave
>  PS Here's the beginner's way I used to parse the ordinal date string (eg
> "2005/17"):
>
> strYear =3D strDate[strDate.index("/")+1, strDate.length]
> strOrdn =3D strDate[0, strDate.index("/")]
>  On 11/18/05, Pe=F1a, Botp <botp@delmonte-phil.com> wrote:
> >
> > davyb [mailto:david.a.boyd@gmail.com]
> >
> > #I have an ordinal date string and I want to change it to an ordinary
> > #date string. For example: 2005/1 should give January 1, 2005. I see
> > #ordinal in the Date class but I need a simple example. Thanks,
> >
> > i hope this is simple enough.
> >
> > # we want to get the year and day values fr your string
> >
> > > re =3D /(\d+)\/(\d+)/ =3D> /(\d+)\/(\d+)/
> > > rs =3D "2005/1" =3D> "2005/1"
> >
> > > y,d=3Dre.match(rs)[1..2] =3D> ["2005", "1"]
> >
> > # we need to convert them to integers since ordinal wants num
> >
> > > y =3D y.to_i =3D> 2005
> > > d =3D d.to_i =3D> 1
> >
> > > od =3D Date.ordinal(y,d) =3D> #<Date: 4906743/2,0,2299161>
> >
> > # we got a date object
> > # fr here we can do anything
> >
> > > od.year =3D> 2005
> > > od.month =3D> 1
> > > od.day =3D> 1
> > > nd_str1 =3D od.to_s =3D> "2005-01-01"
> > > nd_str2 =3D od.strftime("%B %e, %Y") =3D> "January 1, 2005"
> > > nd_str3 =3D nd_str2.squeeze(" ") =3D> "January 1, 2005"
> >
> > hth.
> >
> > kind regards
> > -botp
> >
> > #Dave
> >
> >
>

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