From: Harold Hausman <hhausman@...>
Date: 2005-11-12T03:50:17+09:00
Subject: Re: Accurate Timing in ruby

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That looks legit,
 Wheres that from?
 -Harold

 On 11/11/05, Kroeger, Simon (ext) <simon.kroeger.ext@siemens.com> wrote:
>
> does that help?
>
> ------------------------------------------------------------------------
> --
>
> require "Win32API"
>
> QueryPerformanceCounter =3D Win32API.new("kernel32",
> "QueryPerformanceCounter", 'P', 'I')
> QueryPerformanceFrequency =3D Win32API.new("kernel32",
> "QueryPerformanceFrequency", 'P', 'I')
>
> def get_ticks
> tick =3D ' ' * 8
> get_ticks =3D QueryPerformanceCounter.call(tick)
> tick.unpack('q')[0]
> end
>
> def get_freq
> freq =3D ' ' * 8
> get_freq =3D QueryPerformanceFrequency.call(freq)
> freq.unpack('q')[0]
> end
>
> ticks1 =3D get_ticks
> sleep 1.5
> ticks2 =3D get_ticks
>
> p (ticks2 - ticks1).to_f / (get_freq)
>
> ------------------------------------------------------------------------
> --
>
> cheers
>
> Simon
>
> > -----Original Message-----
> > From: Harold Hausman [mailto:hhausman@gmail.com]
> > Sent: Friday, November 11, 2005 5:04 PM
> > To: ruby-talk ML
> > Subject: Re: Accurate Timing in ruby
> >
> > Silly Windows.
> > I haven't looked at the source but it sounds like it might be using
> > ::GetTickCount(), if thats the case it could probably be
> > refactored to use
> > ::QueryPerformanceCounter() which is a significantly higher resolution
> > timer. Of course, then questions of 9x compatibility come up.
> > The idea of using the SDL wrapper for making a game is
> > probably a good one
> > though.
> > -Harold
> >
> > On 11/11/05, Robert McGovern <robert.mcgovern@gmail.com> wrote:
> > >
> > > > > So my PDA is more accurate than your machine (what OS is that?)
> > > >
> > > > Windows XP.
> > > > I think I got better accuracy on my iBook as well, so
> > it's probably a
> > > > limitation of the OS functions ruby uses to retreive the time on
> > > Windows.
> > >
> > > Mmm, I think your right ... my XP box reports:
> > >
> > > irb(main):001:0> a=3DTime.now;while Time.now=3D=3Da;end;Time.now-a
> > > =3D> 0.016
> > >
> > > for a Athlon 2800.
> > >
> > >
> >
>
>

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