From: ts Date: 2001-05-30T00:55:57+09:00 Subject: [ruby-talk:15940] Re: Regexp (a\1) >>>>> "B" == Benjamin J Tilly writes: B> The example that I gave should give you different results before B> and after your modification. Neither will be what Perl gives. There will be also another difference, but this difference exist also in perl5.6.0 vs perl5.6.1 and I don't know what choice make For example "aba" =~ /^(a(b)?)+$/; 5.6.0 $1 = "a", $2 = "b" 5.6.1 $1 = "a", $2 = "" Guy Decoux