From: ts Date: 2001-05-30T00:16:45+09:00 Subject: [ruby-talk:15938] Re: Regexp (a\1) >>>>> "Y" == Yukihiro Matsumoto writes: Y> Ruby gives same result (before and after the modification). Y> Probably I'm missing something. No this is me which has given the wrong example, sorry "aaaaaa"=~ /^(a\1?){4}$/ must give $1 = "aa" Guy Decoux