[ruby-talk:15633] Q: Function modification/Procedures

Hi,

I'm wondering what the right way to do the following in Ruby, expressed
here in Lisp:

(defun wrap (fn) (lambda (x) (some-fn (fn x))))

I was looking at the Procedure object, but it appears that Procedures
require the
method invocation 'call' to execute the actual procedure body. Is there
syntactic
sugar somehow which makes Procedure objects callable using the "normal"
syntax of
fn(x)? (Somewhat like defining __call__ in Python?) I realize I'm
mashing functional
idioms into an OO language. Perhaps someone can generally enlighten me
as to the right
way to do this kind of thing?

Thanks,
daishi

ps. Please cc me email with responses.