From: "Kroeger Simon (ext)" <simon.kroeger.ext@...>
Date: 2005-09-15T00:22:32+09:00
Subject: Re: Quick and dirty word wrapping.

> -----Original Message-----
> From: Gavin Kistner [mailto:gavin@refinery.com] 
> Sent: Wednesday, September 14, 2005 4:47 PM
> To: ruby-talk ML
> Subject: Re: Quick and dirty word wrapping.
> 
> On Sep 14, 2005, at 8:39 AM, Gavin Kistner wrote:
> > On Sep 14, 2005, at 8:26 AM, Erik Terpstra wrote:
> >
> >> str = 'This is a test of the emergency broadcasting services'
> >> str.scan(/(.{1,30})(?:\s+|$)/)
> >>
> >> => [["This is a test of the"], ["emergency broadcasting"],  
> >> ["services"]]
> >>
> >
> > Nice. Not to golf, but how about simply:
> >
> > str = 'This is a test of the emergency broadcasting services'
> > p str.scan(/.{1,30}\b/)
> > #=> ["This is a test of the ", "emergency broadcasting ", 
> "services"]
> 
> Oops, because mine will split punctuation from its characters.  
> However, both of ours will lose lines that are \S{31,}
> 
> So:
> 
> str = '123456789012345678901234567890This is a test of the emergency  
> broadcasting system. This is only a test.'
> 
> class String
>      def wrap_to( col_width )
>          str = self.gsub( /(\S{#{col_width}})(\S)/, '\1 \2' )
>          str.scan(/(.{1,#{col_width}})(?:\s+|$)/).flatten.join( "\n" )
>      end
> end
> 
> puts str.wrap_to( 30 )
> 123456789012345678901234567890
> [..snip..]


Hmm, nice, just one little thing:

str = '12345678901234567890'
puts str.wrap_to( 10 )
puts
puts str.wrap_to( 5 )

output:

1234567890
1234567890

12345
78901
34567
890

it 'eats' chars...

cheers

Simon