From: ts <decoux@...>
Date: 2001-05-24T00:40:06+09:00
Subject: [ruby-talk:15593] Re: Parse Error

>>>>> "C" == Christian Szegedy <szegedy@or.uni-bonn.de> writes:

C> Shouldn't it be parsed as (a==b)==c, which, of course
C> would produce a runtime error but no parse error...?

  (a == b) == c is not a runtime error

pigeon% ruby -e 'a = b = 12; c = true; p ((a == b) == c)'
true
pigeon% 

 And if you parse it like this, you must also accept 'a < b < c' or
 'a < b > c'  and strange thing like this, which don't give the result than
 some users of a P language expect.


Guy Decoux