From: Sam Mayes <codeslave@...>
Date: 2005-09-01T05:02:57+09:00
Subject: Re: building a gallery layout

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ok here is what i did may not be the most elegant but it works. thanks for=
=20
the help. any Ideas to make it better are welcome.

<table>
<tr>
<th>Company</th>
</tr>
<% counter =3D 0 %>
<% 5.times do %>
<tr>
<% 5.times do %>
<% if @systems[counter] %>
<td>
<table>
<tr>
<td><%=3D @systems[counter].company.name %></td>
<td><%=3D @systems[counter].model %></td>
<td><%=3D @systems[counter].sid %></td>
<td><%=3D @systems[counter].sm_img %></td>
</tr>
<% for price in @systems[counter].prices %>
<tr>
<td><%=3D price.price %></td>
<td><%=3D price.store_name %></td>
<td colspan=3D"2"></td>
</tr>
<% end %>
</table>
</td>
<% else %>
<td></td>
<% end %>
<% counter+=3D1 %>
<% end %>
</tr>
<% end %>=20


</table>


On 8/31/05, Josh Charles <josh.charles@gmail.com> wrote:
>=20
> an array-less way to do it
>=20
> pictures[]
> counter =3D 0
>=20
> 5.times do
> puts "<tr>"
> 5.times do
> if ( pictures[ counter ] ) exists
> puts "<td>" + image code + "</td>"
> else
> puts "<td></td>"
> end
> counter ++
> end
> puts "</tr>"
> end
>=20
> I think that is almost legal ruby code. I'm new to ruby, so I don't
> know exactly. There is probably an even better way of doing this.
> I'm really gray on ruby array handling
>=20
>

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