From: "Simon Kröger" <SimonKroeger@...>
Date: 2005-08-31T20:39:41+09:00
Subject: Re: how to unflatten a flat-array

SHIGETOMI, Takuhiko wrote:

> greetings, William. i'm sorry, your way is beyond my light-weight brain.
> 
> 
>>ary = [1,2,3,4,5,6,7,8]
>>f=nil
>>t=ary.partition{f=!f}
>>p t[0].zip(t[1])
> 
> 
> but it works...
> 
> $ irb
> irb(main):001:0> ary = [1,2,3,4,5,6,7,8]
> => [1, 2, 3, 4, 5, 6, 7, 8]
> irb(main):002:0> f=nil
> => nil
> irb(main):003:0> t=ary.partition{f=!f}
> => [[1, 3, 5, 7], [2, 4, 6, 8]]
> irb(main):004:0> p t[0].zip(t[1])
> [[1, 2], [3, 4], [5, 6], [7, 8]]
> => nil
> 
> i'd like you use a terrestrial language, or beam me your universal
> translator. :-)
> 


Muhahaha...

p ary.zip((0...ary.size).to_a).partition{|o|(o[1]%2).zero?}.
map{|a|a.transpose[0]}

erm, sorry, could not resist :)

But transpose make the example above shorter (and perhaps even
more readable):

f=nil
p ary.partition{f=!f}.transpose

cheers

Simon