From: Kevin <kevin_olbrich@...>
Date: 2005-07-30T00:51:02+09:00
Subject: Re: The while loop for calculating a power of a number less than another number?

this is odd since you don't need to loop to find the answer

maxnum = 10_000

n = 2 ** (Math.log(maxnum) / Math.log(2)).floor

puts n + " is the largest power of 2 less than " + maxnum