From: Stefan Lang <langstefan@...>
Date: 2005-07-29T20:37:09+09:00
Subject: Re: [newbie] make local var visible

On Friday 29 July 2005 13:09, "Pe�a, Botp" wrote:
> #>> I think you have 2 options here (maybe more, but these are
> #the ones I
> #>> can come up with as a newbie myself):
> #
> #four and counting...
> #
> #>> 1) pass foo as an argument.
> #>>   def mfoo(foo) ... end
> #>>   mfoo(foo)
> #>> 2) make foo an instance-variable
> #>>   @foo = [..]
> #>>   def mfoo
> #>>      @foo.each...
> #>>   end
> #>
> #> or make it global (sigh): $foo
> #
> #or make a proc from the method
>
>
> Hi Brian/Cristi/Wannes/Kroeger/Kero, and others,
>
> Yes. I've done what you have all suggested. Thank you.
> But I was hoping for something "cleaner". Sorry.
>
> Can we request RCR for this?

IMHO not necessary. Ruby already has what you want. You
want a closure.

foo=["a","b","c"]

mfoo = lambda do
� � foo.each do |f|
� � � � p f
� � end
end

mfoo.call

-- 
Stefan