From: Ezra Zygmuntowicz <ezra@...>
Date: 2005-06-11T09:34:24+09:00
Subject: Re: Regex help


On Jun 10, 2005, at 5:21 PM, Nikolai Weibull wrote:

> Ezra Zygmuntowicz wrote:
>
>
>> Say that I have a string like this:
>>
>> "SPT_051205.jpg"
>>
>> How could I strip out the numbers that stand for the date and convert
>> it to look like this:
>>
>> "May 12 2005"
>>
>>
>
> "SPT_051205.jpg".scan(/(\d\d)(\d\d)(\d\d)/) do |a|
>   puts Time.mktime(a[2].to_i + 2000, a[0].to_i, a[1].to_i).strftime 
> ("%b %d %Y")
> end
>
> Enjoy,
>         nikolai
>

Thanks so much Nikolai it works perfect!
-Ezra
> -- 
> Nikolai Weibull: now available free of charge at http://bitwi.se/!
> Born in Chicago, IL USA; currently residing in Gothenburg, Sweden.
> main(){printf(&linux["\021%six\012\0"],(linux)["have"]+"fun"-97);}
>

-Ezra Zygmuntowicz
Yakima Herald-Republic
WebMaster
509-577-7732
ezra@yakima-herald.com