From: Robert Klemme <bob.news@...>
Date: 2005-06-10T16:00:28+09:00
Subject: Re: newbieQ: new array from old array w regex

nobuyoshi nakada wrote:
> Hi,
>
> At Fri, 10 Jun 2005 13:15:28 +0900,
> Charles L. Snyder wrote in [ruby-talk:145032]:
>> This only gives me the entire contents of the address node - how do I
>> extract only the zip codes (preferably putting them in an array). My
>> next step is to end up with a hash table of unique zipcodes and
>> their frequency of occurrence...
>
> Enumerable#each just returns the receiver itself.
>
>    puts mylist.grep(/b\d{5}-\d{4}\b|\b\d{5}\b/)

You still get the complete string.  This one might work better

puts mylist.inject([]){|res,e| res << $& if /\b\d{5}(?:-\d{4})?\b/ =~ e;
res}

Also, could it be that the leading backslash for the word boundary was
missing in the original rx?

Kind regards

    robert