From: Pixel <pixel@...>
Date: 2001-04-28T20:00:52+09:00
Subject: [ruby-talk:14374] Re: || .. or Question

matz@zetabits.com (Yukihiro Matsumoto) writes:

> Hi,
> 
> In message "[ruby-talk:14268] Re: || .. or Question"
>     on 01/04/27, Marko Schulz <in6x059@public.uni-hamburg.de> writes:
> 
> |Why is 'n == 3 or n == 5' not an expression? And 
> |why is 'n == 3 || n == 5' on the other hand one? 
> 
> Simply precedence reason. 

about surprising precedence:

Math.sqrt (1-2).abs       is      (Math.sqrt(1-2)).abs
p (1..10).to_a            is      (p(1..10)).to_a


but

return (1-2).abs          is      return((1-2).abs)

which show that "return" is parsed differently even if it has a functional
syntax just like "Math.sqrt". "return" has a lower precedence


cu Pixel.