From: jean Date: 2005-05-20T22:05:15+09:00 Subject: Multiple return and parallel assignement Hi, I'm studying Ruby and I'm glad to find similar behaviours of two common lisp operators that I like: parallel assignement has a similar behavior of the 'let' special operator while the multiple-return is similar to 'values'. A little difference (syntax apart :-)) is that if in common lisp you make available only one variable to contains the return values of an expression it gets the first value returned and not an array with all the values as in ruby: An example may be useful, in lisp: CL-USER> (defvar myvar) MYVAR CL-USER> (defun mymethod () (values 1 2)) MYMETHOD CL-USER> (setf myvar (mymethod)) 1 CL-USER> myvar 1 CL-USER> In ruby: irb(main):003:0> def mymethod return 1, 2 end irb(main):005:1> nil irb(main):006:0> a = mymethod [1, 2] irb(main):007:0> a [1, 2] irb(main):008:0> Thinking at the use I've found of the multiple return I find that perhaps the common lisp choice is more pragmatic beacause usually the multiple return is used to define method where in the 99% of cases is taken only the first element and in few cases the rest. In common lisp for example the gethash function for the hashtable returns 2 values, the value in the hash associated at the key and a boolean value that is true if the value returned is in the hashtable or false if is the default value. In most of cases this boolean is ignored and in the code you assign only the first returned value at a variable: CL-USER> (setf myvar (gethash key my-hashtable)) What do you think about? (Perhaps I don't know enough Ruby and there is a way to do the same thing in Ruby ;-) ) Thinking at Ruby I'd like that if I call mymethod defined above with only a variable it gets the first value: irb(main):006:0> a = mymethod 1 irb(main):007:0> a 1 irb(main):008:0> and if use a variable with * then it gets an array with all the values: irb(main):006:0> *a = mymethod [1, 2] irb(main):007:0> a [1, 2] irb(main):008:0> What do you think about? Thanks in advance. Giannandrea