From: Adriano Ferreira <a.r.ferreira@...>
Date: 2005-04-25T21:53:18+09:00
Subject: Re: Array::new

> foo = Array.new(3,Array.new)
> foo = Array.new(3,[])

I think these are just the same. Indeed, the object creation ([] or
Array.new) happens only once. To have distinct arrays in every slot of
foo you need something like

foo = Array.new(3) { Array.new }
foo[0] << 4
foo[1] << 5
foo[0] << 6
p foo

(as Dave Baldwin suggested) and you'll get

[[4, 6], [5], []]

If you come to this code, by looking at the Array documentation where
the example
            Array.new(2, Hash.new)  � [{}, {}]  
is given, I agree that this documentation is misleading for beginners.

Regards,
Adriano.